6b+7b+2b^2=15b^2

Solution for 6b+7b+2b^2=15b^2 equation:

6b+7b+2b^2=15b^2

We move all terms to the left:

6b+7b+2b^2-(15b^2)=0

determiningTheFunctionDomain
2b^2-15b^2+6b+7b=0

We add all the numbers together, and all the variables

-13b^2+13b=0

a = -13; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-13)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-13}=\frac{-26}{-26}
=1
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-13}=\frac{0}{-26}
=0
$